Elements X, Y, and Z are configured in the following ways in terms of their electronic configuration:<br><br> X=2,4; Y=2,7; Z =2,1 <br><br> Which two elements will combine to form an ionic compound, and what is the correct formula for that compound,

Practice MCQ for SSC, UPSC, RRB Exams

X_{2} Y

Z Y

X Z_{3}

Y_{2} Z

Correct Answer: B সঠিক উত্তর: B

Explanation ব্যাখ্যা

To solve this, let's first identify the elements based on their electronic configurations:
X = 2,4 → Atomic number = 6 → Carbon (C)
Y = 2,7 → Atomic number = 9 → Fluorine (F)
Z = 2,1 → Atomic number = 3 → Lithium (Li)

Now consider their tendencies:
X (Carbon): Has 4 valence electrons → Tends to form covalent bonds, not ionic.
Y (Fluorine): Has 7 valence electrons → Needs 1 electron → very electronegative → typically gains electrons.
Z (Lithium): Has 1 valence electron → Easily loses it to form Li⁺ → typical metal.

Ionic bond: Occurs between metal (electron donor) and non-metal (electron acceptor).
Z (Li) can donate 1 electron.
Y (F) can accept 1 electron.

So, Z and Y can form an ionic compound:
LiF → ZY

Correct answer: b) ZY

Elements X, Y, and Z are configured in the following ways in terms of their electronic configuration: X=2,4; Y=2,7; Z =2,1 Which two elements will combine to form an ionic compound, and what is the correct formula for that compound, are you asking?

Practice MCQ for SSC, UPSC, RRB Exams

Correct Answer: B সঠিক উত্তর: B

Explanation ব্যাখ্যা

Related Questions সম্পর্কিত প্রশ্ন

Elements X, Y, and Z are configured in the following ways in terms of their electronic configuration:

X=2,4; Y=2,7; Z =2,1

Which two elements will combine to form an ionic compound, and what is the correct formula for that compound, are you asking?