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Elements X, Y, and Z are configured in the following ways in terms of their electronic configuration:

X=2,4; Y=2,7; Z =2,1

Which two elements will combine to form an ionic compound, and what is the correct formula for that compound, are you asking?

Practice MCQ for SSC, UPSC, RRB Exams

X_{2} Y

Z Y

X Z_{3}

Y_{2} Z

Correct Answer: B সঠিক উত্তর: B

Explanation ব্যাখ্যা

To solve this, let's first identify the elements based on their electronic configurations:
X = 2,4 → Atomic number = 6 → Carbon (C)
Y = 2,7 → Atomic number = 9 → Fluorine (F)
Z = 2,1 → Atomic number = 3 → Lithium (Li)

Now consider their tendencies:
X (Carbon): Has 4 valence electrons → Tends to form covalent bonds, not ionic.
Y (Fluorine): Has 7 valence electrons → Needs 1 electron → very electronegative → typically gains electrons.
Z (Lithium): Has 1 valence electron → Easily loses it to form Li⁺ → typical metal.

Ionic bond: Occurs between metal (electron donor) and non-metal (electron acceptor).
Z (Li) can donate 1 electron.
Y (F) can accept 1 electron.

So, Z and Y can form an ionic compound:
LiF → ZY

Correct answer: b) ZY

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Elements X, Y, and Z are configured in the following ways in terms of their electronic configuration: X=2,4; Y=2,7; Z =2,1 Which two elements will combine to form an ionic compound, and what is the correct formula for that compound, are you asking?