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The equivalent weight of NaOH is:

Practice MCQ for SSC, UPSC, RRB Exams

A. 40 A.

B. 20 B.

C. 23 C.

D. 80 D.

Equivalent weight =

\frac{Molar mass of NaOH}{n - factor}

Molar mass of NaOH = 23 (Na) + 16 (O) + 1 (H) = 40 g/mol
n-factor (number of replaceable OH⁻ ions) = 1
Equivalent weight of NaOH= 40/1 = 40 g

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