Three resistors 6 Ω, 4 Ω and 5 Ω are combined in parallel. What is the total resistance of the combination?

A. 37/60 Ω A.

B. 51 Ω B.

C. 60/37 Ω C.

D. None of the above D.

Correct Answer: C সঠিক উত্তর: C

Explanation ব্যাখ্যা

To find the total resistance of resistors combined in parallel, we can use the formula for equivalent parallel resistance:
1/R=1/R1+1/R2+1/R3
where:
(R) is the equivalent parallel resistance.
(R1), (R2), and (R3) are the resistances of the individual resistors.
Given Resistances:
(R1=6 ohm, R2= 4 ohm, R3 = 5ohm)
Applying the Formula:
1/R = 1/6 + 1/4 + 1/5
Therefore, Taking the Reciprocal: R = 60/37
Therefore, the total resistance of the combination is approximately 60/37 ohm

Three resistors 6 Ω, 4 Ω and 5 Ω are combined in parallel. What is the total resistance of the combination?

Practice MCQ for SSC, UPSC, RRB Exams

Correct Answer: C সঠিক উত্তর: C

Explanation ব্যাখ্যা

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