Total distance covered = 88 km = 88000 m
Number of revolutions = 2000
Distance covered in 1 revolution = Circumference of wheel
\( = \frac{88000}{2000} = 44 \text{ m} \)
Circumference of a circle:
\( 2\pi r = 44 \)
Using \( \pi = \frac{22}{7} \):
\( 2 \times \frac{22}{7} \times r = 44 \)
\( \frac{44}{7} \times r = 44 \)
\( r = 7 \text{ m} \)
Correct Answer: Option C (7 m)
মোট দূরত্ব = 88 km = 88000 m
মোট ঘূর্ণন সংখ্যা = 2000
1 বার ঘোরায় অতিক্রান্ত দূরত্ব = চাকাটির পরিধি
\( = \frac{88000}{2000} = 44 \text{ m} \)
বৃত্তের পরিধি:
\( 2\pi r = 44 \)
\( \pi = \frac{22}{7} \) বসাই:
\( 2 \times \frac{22}{7} \times r = 44 \)
\( \frac{44}{7} \times r = 44 \)
\( r = 7 \text{ m} \)
সঠিক উত্তর: Option C (7 m)
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