Using Heron’s Formula:
\[ a = 26,\; b = 28,\; c = 30 \]
Semi-perimeter:
\[ s = \frac{26 + 28 + 30}{2} = \frac{84}{2} = 42 \]
Area:
\[ \text{Area} = \sqrt{s(s-a)(s-b)(s-c)} \]
\[ = \sqrt{42(42-26)(42-28)(42-30)} \]
\[ = \sqrt{42 \times 16 \times 14 \times 12} \]
\[ = \sqrt{112896} = 336 \]
Therefore, Area = \[ 336 \text{ sq cm} \]
Heron’s Formula ব্যবহার করি:
\[ a = 26,\; b = 28,\; c = 30 \]
অর্ধপরিসীমা:
\[ s = \frac{26 + 28 + 30}{2} = \frac{84}{2} = 42 \]
ক্ষেত্রফল:
\[ \text{Area} = \sqrt{s(s-a)(s-b)(s-c)} \]
\[ = \sqrt{42(42-26)(42-28)(42-30)} \]
\[ = \sqrt{42 \times 16 \times 14 \times 12} \]
\[ = \sqrt{112896} = 336 \]
অতএব ক্ষেত্রফল = \[ 336 \text{ sq cm} \]
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