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A car moves around a circular track with constant speed. Its acceleration is:
একটি গাড়ি ধ্রুব বেগে একটি বৃত্তাকার পথে চলছে। এর ত্বরণের দিক হবে—
Practice MCQ for SSC, UPSC, RRB Exams
A. Zero
A. শূন্য
B. Directed outwards
B. বাইরের দিকে
C. Directed towards the centre
C. কেন্দ্রের দিকে
D. Along the velocity
D. বেগের দিকে
Correct Answer: C
সঠিক উত্তর: C
Explanation
ব্যাখ্যা
When a car moves in a circular path with constant speed, the motion is called
uniform circular motion
.
Although the speed remains constant, the
direction of velocity continuously changes
.
Since velocity is a vector quantity, a change in direction means there is acceleration.
This acceleration is called
centripetal acceleration
.
The centripetal acceleration is given by:
\(a_c=\dfrac{v^2}{r}\)
It always acts
towards the centre of the circular path
.
Important:
In uniform circular motion:
Velocity → Tangential direction
Acceleration → Towards the centre
Therefore, the acceleration of the car is directed towards the centre.
যখন কোনো গাড়ি ধ্রুব বেগে বৃত্তাকার পথে চলে, তখন সেই গতিকে
সমবৃত্তীয় গতি (Uniform Circular Motion)
বলে।
এক্ষেত্রে বেগের মান ধ্রুব থাকলেও
বেগের দিক ক্রমাগত পরিবর্তিত হয়
।
যেহেতু বেগ একটি ভেক্টর রাশি, তাই দিক পরিবর্তনের ফলে ত্বরণ সৃষ্টি হয়।
এই ত্বরণকে
কেন্দ্রাভিমুখী ত্বরণ বা অভিকেন্দ্র ত্বরণ (Centripetal Acceleration)
বলে।
কেন্দ্রাভিমুখী ত্বরণের সূত্র:
\(a_c=\dfrac{v^2}{r}\)
এটি সর্বদা
বৃত্তাকার পথের কেন্দ্রের দিকে
ক্রিয়া করে।
গুরুত্বপূর্ণ:
সুষম বৃত্তীয় গতিতে:
বেগ → স্পর্শকের দিকে
ত্বরণ → কেন্দ্রের দিকে
অতএব, গাড়ির ত্বরণ
কেন্দ্রের দিকে
নির্দেশিত হয়।
Related Questions
সম্পর্কিত প্রশ্ন
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